X^2-104x+250=0

Solution for X^2-104x+250=0 equation:

X^2-104X+250=0

a = 1; b = -104; c = +250;
Δ = b2-4ac
Δ = -1042-4·1·250
Δ = 9816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9816}=\sqrt{4*2454}=\sqrt{4}*\sqrt{2454}=2\sqrt{2454}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-2\sqrt{2454}}{2*1}=\frac{104-2\sqrt{2454}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+2\sqrt{2454}}{2*1}=\frac{104+2\sqrt{2454}}{2}
$